метод ready() принимает значение false

public class Solution {
    public static volatile BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    public static void main(String[] args) throws InterruptedException {
        Read3Strings t1 = new Read3Strings();
        Read3Strings t2 = new Read3Strings();
        t1.start();
        t1.join();
        t2.start();
        t2.join();
        t1.printResult();
        t2.printResult();
    }
    public static class Read3Strings extends Thread{
        String result = "";
        public void run(){
            String s1 = "";
            String s2 = "";
            String s3 = "";
            try {
                if (reader.ready()) {
                    try {
                        s1 = reader.readLine();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
            try {
                if (reader.ready()) {
                    try {
                        s2 = reader.readLine();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
            try {
                if (reader.ready()) {
                    try {
                        s3 = reader.readLine();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
            result = s1 + " " + s2 + " " + s3;
        }
        public void printResult(){
            System.out.println(result);
        }
    }
}