Не принимает казалось бы правильное решение

package com.javarush.task.task19.task1918; import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; /* Знакомство с тегами */ public class Solution { public static void main(String[] args) { String teg = args[0];//"span";// String startTeg = "<"+teg; String fileName = "F:File1.txt"; String text = ""; try(BufferedReader reader = new BufferedReader(new InputStreamReader(System.in))){ fileName = reader.readLine(); }catch (IOException ex){} try(BufferedReader reader1 = new BufferedReader(new FileReader(fileName))){ while(reader1.ready()){ text+= reader1.readLine(); } }catch(IOException exep){} List<String>newList = tegParsers(text,teg); for(String str: newList){ System.out.println(str); } } public static List<String> tegParsers(String text,String teg){ List<String> tegess = new ArrayList<>(); List<Integer> startIndexInTeg = new ArrayList<>(); List<Integer> endIndexInTeg = new ArrayList<>(); int quantityStart = 0; int quantityEnd = 0; String endTeg = "</"+teg+">"; String starterTeg = "<"+teg; int startIndex = 0; int endIndex = text.length(); int secondStart = 0; int secondEnd = 0; for(int i = 0;i<text.length();i++){ char current = text.charAt(i); if((current == '<') && text.charAt(i+1)!='/'&&text.substring(i,i+starterTeg.length()).equals(starterTeg) ) { quantityStart++; if(quantityStart<2){ startIndex = i; }else{ startIndexInTeg.add(i); } }else if((current == '<') && text.charAt(i+1)=='/'&&text.substring(i,i+endTeg.length()).equals(endTeg)){ quantityEnd++; if(quantityEnd==quantityStart){ endIndex = i+endTeg.length(); tegess.add(text.substring(startIndex,endIndex)); if(quantityStart>1&&quantityEnd>1){ for(int j = 0; j<startIndexInTeg.size();j++){ tegess.add(text.substring(startIndexInTeg.get(j),endIndexInTeg.get(j))); } startIndexInTeg.clear(); endIndexInTeg.clear(); } quantityEnd=0; quantityStart=0; }else{ endIndexInTeg.add(i+endTeg.length()); } } } return tegess; } }