Manakala Loop di Jawa

• teruskan – menghentikan pelaksanaan badan gelung semasa dan bergerak ke ungkapan logik operator sementara. Jika ungkapan yang dikira adalah benar, pelaksanaan gelung akan diteruskan.
• putus – segera menghentikan pelaksanaan gelung semasa dan melompat ke arahan pertama di luarnya. Oleh itu, pelaksanaan gelung semasa terganggu. Kami akan melihatnya dengan lebih terperinci dalam topik seterusnya.

while(числоЯблокВТазике>0) {
    яблоко = тазик.взятьОчередноеЯблоко();
    числоЯблокВТазике--;//-- this is a decrement, reduces the number of apples by one
    if (яблоко.плохое()) {  // method will return true for rotten, etc. apples
        яблоко.выкинутьВМусор();
        continue; // continue the loop, go to the condition number ofApplesIn the Basin>0
    }
    положитьВПирог(яблоко.чистить().нарезать());
}

public static void main(String[] args) {
    int sum = 0;    // total amount
    int i = 0;      // starting number of the row
    int count = 20; // amount of numbers
    while(i<=count) {
        i++;        // take the next number, i++ is equivalent to i=i+1
        if (i*i<=count)  // if the square of the number is less
            continue;   // number of numbers - do not count the sum
                        // move on to the next number in the loop
        sum += i*i*i; // otherwise, we calculate the sum of cubes of numbers
    } // sum += i*i*i - notation similar to sum = sum + i*i*i
    System.out.println(sum);// print result
}

Kitaran yang tidak berkesudahan

while(true) {
    // Loop body
}

public static void main(String[] args) {
    int number = 3; // Number to be raised to a power
    int result = 1; // Result of exponentiation
    int power = 1; // Initial exponent
    while(true) {
        result = result * number;
        System.out.println(number + "to the extent" + power + " = " + result);
        power++;
        if (power>10)
            break; // exit from the loop
    }
}

3 в степени 1 = 3
3 в степени 2 = 9
3 в степени 3 = 27
3 в степени 4 = 81
3 в степени 5 = 243
3 в степени 6 = 729
3 в степени 7 = 2187
3 в степени 8 = 6561
3 в степени 9 = 19683
3 в степени 10 = 59049
Process finished with exit code 0

Gelung Bersarang

1. Jika terdapat epal dalam besen, ikut langkah 1.1 hingga 1.4:

   1. 1.1. Ambil sebiji epal
   2. 1.2. Bersihkan dan potong menjadi kepingan
   3. 1.3. Letakkan di atas dasar pai pastri dalam kuali
   4. 1.4. Mari kita kembali ke langkah 1.

1. Bilangan kepingan = 0

2. Walaupun bilangan kepingan adalah < 12, ikut langkah 2.1 hingga 2.3

   1. 2.1. Potong satu lagi kepingan dari epal
   2. 2.2. Bilangan kepingan ++
   3. 2.3. Kembali ke langkah 2

1. Jika terdapat epal di dalam besen, maka ikuti langkah 1.1 hingga 1.6:

   1. 1.1. Ambil sebiji epal
   2. 1.2. Kupas ia
   3. 1.3. Bilangan kepingan = 0
   4. 1.4. Пока число долек < 12, выполнить шаги с 1.4.1 по 1.4.3
   1. 1.4.1. Отрезать очередную дольку от яблока
   2. 1.4.2. Кол-во долек ++
   1.4.3. Возвращаемся на шаг 1.4
   5. 1.5. Помещаем дольки на тестовое основание пирога из теста на сковороде
   6. 1.6. Возвращаемся на шаг 1.

public static void main(String[] args) {
    // Display the values ​​of the second multiplier in the line
    System.out.println("    2  3  4  5  6  7  8  9");
    int i = 2;      // first multiplier, assign starting value
    while(i<10) {   // First loop, execute while the first multiplier is less than 10
        System.out.print(i + " | ");// Display the first multiplier at the beginning of the string
        int j = 2;                  // second multiplier, starting value
        while (j<10) { // Second loop, execute while the second multiplier is less than 10
            int mul=i*j; // Calculate the product of factors
            if (mul<10)  // If it contains one digit, print two spaces after it
                System.out.print(mul + "  ");
            else   // otherwise output the product and after it - one space
                System.out.print(mul + " ");
            j++;     // Increase the second multiplier by one,
        }            // Go to the beginning of the second loop (while (j<10 ).... )
        System.out.println(); // Move to the next line of output
        i++;                  // Increase the first multiplier by one,
    }                         // Go to the beginning of the first loop (while ( i<10 ) ....
}

2  3  4  5  6  7  8  9

2 | 4  6  8  10 12 14 16 18 

3 | 6  9  12 15 18 21 24 27

4 | 8  12 16 20 24 28 32 36

5 | 10 15 20 25 30 35 40 45

6 | 12 18 24 30 36 42 48 54

7 | 14 21 28 35 42 49 56 63

8 | 16 24 32 40 48 56 64 72

9 | 18 27 36 45 54 63 72 81

Process finished with exit code 0