Решение, вероятно всего не верное, но вопрос вот в чем, почему после прохождения второго круга цикл заканчивает свою работу?
package com.javarush.task.task22.task2207;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.LinkedList;
import java.util.List;
/*
Обращенные слова
*/
public class Solution {
public static List<Pair> result = new LinkedList<>();
public static void main(String[] args) throws IOException {
try (BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
BufferedReader fileReader = new BufferedReader(new FileReader(reader.readLine()))) {
String c = "";
StringBuilder str = new StringBuilder(c);
while (fileReader.ready()) {
str.append(fileReader.readLine()).append(" ");
}
String[] split = str.toString().split(" ");
ArrayList<String> list = new ArrayList<>(Arrays.asList(split));
ArrayList<String> reverselist = new ArrayList<>();
for (String reverse : list) {
StringBuilder sb = new StringBuilder(reverse);
reverselist.add(sb.reverse().toString());
}
Pair pair = new Pair();
for (int i = 0; i < list.size(); i++) {
if (list.get(i).equals(reverselist.get(i))){
pair.first = list.get(i);
pair.second = reverselist.get(i);
result.add(pair);
}
}
}
}
public static class Pair {
String first;
String second;
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Pair pair = (Pair) o;
if (first != null ? !first.equals(pair.first) : pair.first != null) return false;
return second != null ? second.equals(pair.second) : pair.second == null;
}
@Override
public int hashCode() {
int result = first != null ? first.hashCode() : 0;
result = 31 * result + (second != null ? second.hashCode() : 0);
return result;
}
@Override
public String toString() {
return first == null && second == null ? "" :
first == null ? second :
second == null ? first :
first.compareTo(second) < 0 ? first + " " + second : second + " " + first;
}
}
}